x^2+4=2x^2+5

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Solution for x^2+4=2x^2+5 equation: 



x^2+4=2x^2+5

We move all terms to the left:

x^2+4-(2x^2+5)=0

We get rid of parentheses

x^2-2x^2-5+4=0

We add all the numbers together, and all the variables

-1x^2-1=0

a = -1; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-1)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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